An object uniformly accelerates from 15.0m/s west to 35.0m/s west. What is the rate of acceleration if the displacement during this time was 43.0m?

Answer 1

The kinematic equation that should be applied to solve this issue is

#v_"f"^"2"# = #v_"i"^"2"# + #2ad#, where
#v_"f"^"2"# is the final velocity squared #v_"i"^"2"# if the initial velocity squared #a# is acceleration #d# = displacement
Known: #v_"i"# = 15.0m/s #v_"f"# = 35.0m/s #d# = 43.0m
Unknown: #a#
Equation manipulated to solve for #a#:
(#v_"f"^"2" - v_"i"^"2")"/"2d = a#

Resolution:

#(35.0m"/s")"^2# - #(15.0m"/s")"^2##/##(2)(43.0m)# = #a#
#(1230m^2"/s"^2# - #225m^2"/s"^2)##/##86.0m# =
#(1005m^2"/s"^2)##/##(86.0m)# = #11.7m"/s"^2#
Acceleration is #11.7m"/s"^2#
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Answer 2

The rate of acceleration is (1.25 , \text{m/s}^2) west.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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