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An object travels North at #1 m/s# for #3 s# and then travels South at #2 m/s# for #4 s#. What are the object's average speed and velocity?

Answer 1

See below....

As the object goes through north,he overcame the distance #(1×3)=3m# As the object goes through south, he overcame #(4×2)=8m# Hence,its net displacement is #(8-3)=5m# by south. Its average speed is (distance covered/time)=#(8+3)/(3+4)=1.57ms^-1# and average velocity is(displacement/time) #=5/(3+4)=0.71ms^-1#

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Answer 2

Julia Aguilar

Average speed: ( \frac{Total:distance}{Total:time} = \frac{3:m + 4:m}{3:s + 4:s} = \frac{7:m}{7:s} = 1:m/s )

Average velocity: ( \frac{Displacement}{Total:time} = \frac{(-3:m) + (4:m)}{3:s + 4:s} = \frac{1:m}{7:s} ) North

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.