# An object's two dimensional velocity is given by #v(t) = ( sqrt(3t)-t , t^2-5t)#. What is the object's rate and direction of acceleration at #t=2 #?

The rate of acceleration is

The derivative of the velocity is the acceleration.

The acceleration rate is

The third quadrant represents the direction.

By signing up, you agree to our Terms of Service and Privacy Policy

To find the acceleration, differentiate the velocity function with respect to time. Then, substitute t=2 into the acceleration vector.

Acceleration at t=2 is (1, -6), and the direction is along the vector (1, -6).

By signing up, you agree to our Terms of Service and Privacy Policy

- An object is thrown vertically from a height of #15 m# at # 19 m/s#. How long will it take for the object to hit the ground?
- If a stone is dropped at an altitude of 174.9 m from a helicopter which is ascending with a velocity of 20.68 m/s, how long does the stone take to reach the ground?
- Since an airplane has no brakes, how does an airplane slow down?
- A ball is dropped from a height of 10 feet.Each time it hits the ground, it bounces to 80% of it's previous height. Find the total distance travelled by the ball?
- An object's two dimensional velocity is given by #v(t) = ( t-2t^3 , 4t^2-t)#. What is the object's rate and direction of acceleration at #t=2 #?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7