# An object's two dimensional velocity is given by #v(t) = ( 3t^2 - 5t , t )#. What is the object's rate and direction of acceleration at #t=2 #?

I'm guessing they're using normal convention replaced by brackets.

In the end, you'll get why the answer is as given in the box.

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Rate of acceleration at (t=2): ( (6 , \text{m/s}^2, 2 , \text{m/s}^2) )

Direction of acceleration at (t=2): ( \theta = \arctan\left(\frac{2}{6}\right) )

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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