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An object is thrown vertically at a height of #14 m# at #1 m/s#. How long will it take for the object to hit the ground?

Answer 1

Nathan Ashcroft

#t=1,59 " s"#
#t=1,69 " s"#

#" if object is thrown downward:"#

#v_i=1m/s# #y=14m# #g=9,81m/s^2#

#y=v_i*t+1/2*g*t^2# #14=1*t+1/2*9,81*t^2#

#4,905t^2+t-14=0#

#Delta=sqrt(1^2+4*4,905*14)#

#Delta=sqrt(1+274,68)#

#Delta=sqrt(275,68)# #Delta=16,60# #t=(-1+16,60)/(2*4,905)#

#t=(15,60)/(9,81)# #t=1,59 " s"# #"if object is thrown upward :"# #t_u=v_i/g" "t_u=1/(9,81)" "t_u=0,10" s"# #"elapsed time to reach peak point"# #h=v_i^2/(2*g)#

#h=1/(2*9,81)" "h=0,05" m"# #h_t=14+0,05=14,05" meters total height" #

#14,05=1/2*g*t^2" "28,1=9,81*t^2#

#t^2=(28,1)/(9,81)#

#t^2=2,86#

#t=1,69 " s"#

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Answer 2

Nathan Ashcroft

The time it takes for the object to hit the ground is approximately 1.87 seconds.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.