An object is at rest at #(4 ,1 ,6 )# and constantly accelerates at a rate of #4/3 m/s^2# as it moves to point B. If point B is at #(3 ,5 ,6 )#, how long will it take for the object to reach point B? Assume that all coordinates are in meters.

Answer 1

The time is #=2.49s#

The distance between the points #A=(x_A,y_A,z_A)# and the point #B=(x_B,y_B,z_B)# is
#AB=sqrt((x_B-x_A)^2+(y_B-y_A)^2+(z_B-z_A)^2)#
#d=AB= sqrt((3-4)^2+(5-1)^2+(6-6)^2)#
#=sqrt(1^2+4^2+0^2)#
#=sqrt(1+16)#
#=sqrt17#
#=4.123m#

We utilize the equation of motion.

#d=ut+1/2at^2#
#u=0#

thus,

#d=1/2at^2#
#a=5/4ms^-2#
#t^2=(2d)/a=(2*4.123)/(4/3)#
#=6.18s^2#

t = sqrt(6.18) = 2.49 s

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Answer 2

To find the time it takes for the object to reach point B, we can use the formula for displacement with constant acceleration:

[ \Delta x = v_0 t + \frac{1}{2} a t^2 ]

Where:

  • ( \Delta x ) is the displacement (distance) between the initial position and point B.
  • ( v_0 ) is the initial velocity, which is 0 since the object is at rest initially.
  • ( a ) is the acceleration rate, given as ( 4/3 ) m/s^2.
  • ( t ) is the time taken to reach point B.

Given:

  • Initial position: ( (x_0, y_0, z_0) = (4, 1, 6) )
  • Final position (point B): ( (x, y, z) = (3, 5, 6) )

First, find the displacement in each dimension:

  • ( \Delta x = x - x_0 = 3 - 4 = -1 )
  • ( \Delta y = y - y_0 = 5 - 1 = 4 )
  • ( \Delta z = z - z_0 = 6 - 6 = 0 )

Substitute into the displacement formula:

[ -1 = 0 \cdot t + \frac{1}{2} \left(\frac{4}{3}\right) t^2 ]

Solve for ( t ):

[ \frac{1}{2} \left(\frac{4}{3}\right) t^2 = -1 ]

[ \frac{2}{3} t^2 = -1 ]

[ t^2 = -\frac{3}{2} ]

Since time cannot be negative, there is no real solution. This means that the object will never reach point B. There might be a mistake in the provided information or assumptions made.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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