# An object is at rest at #(2 ,1 ,5 )# and constantly accelerates at a rate of #3 m/s# as it moves to point B. If point B is at #(6 ,7 ,5 )#, how long will it take for the object to reach point B? Assume that all coordinates are in meters.

It will take

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To calculate the time it takes for the object to reach point B, you can use the kinematic equation:

[ s = ut + \frac{1}{2}at^2 ]

where:

- ( s ) is the displacement (distance between the initial and final positions),
- ( u ) is the initial velocity (which is 0 since the object is at rest),
- ( a ) is the acceleration,
- ( t ) is the time.

Rearrange the equation to solve for ( t ):

[ t = \sqrt{\frac{2s}{a}} ]

Substitute the values:

[ t = \sqrt{\frac{2 \sqrt{(6-2)^2 + (7-1)^2 + (5-5)^2}}{3}} ]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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