An ellipsoid has radii with lengths of #2 #, #8 #, and #5 #. A portion the size of a hemisphere with a radius of #3 # is removed form the ellipsoid. What is the volume of the remaining ellipsoid?

Answer 1

The volume is #=278.6 u^3#

Volume of ellipsoid is #=4/3piabc#
Volume of henisphere is #=2/3pir^3#
Remaining volume #=4/3piabc-2/3pir^3#
#=2/3pi(2abc-r^3)#
#=2/3pi(2*2*8*5-3^3)#
#=2/3pi(160-27)#
#=2/3pi*133#
#=278.6#
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Answer 2

To find the volume of the remaining ellipsoid after removing a hemisphere, use the formula for the volume of an ellipsoid:

Volume = (4/3) * π * a * b * c

Where 'a', 'b', and 'c' are the semi-axes lengths of the ellipsoid. In this case, 'a' = 2, 'b' = 8, and 'c' = 5.

First, calculate the volume of the entire ellipsoid using the given semi-axes lengths. Then, calculate the volume of the removed hemisphere with a radius of 3.

Finally, subtract the volume of the hemisphere from the volume of the entire ellipsoid to find the volume of the remaining ellipsoid.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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