An elevator car weighs 5500 N. If the car accelerates upwards at a rate of 4.0 m/s2, what is the tension in the support cable lifting the car?

Thanks for helping.

Answer 1

#"The tension in the support cable is 7755 Newtons."#

#G:"represents weight of elevator(the red vector)"#
#F:"Force by inertia(the blue vector)"#
#T:"Tension in the cable"#

#T=F+G#

#T=m*a+G#

#m:"represents mass of elevator"#
#G=m*g#

#5500=m*g#

#m=5500/(9.81)#

#T=5500/(9.81)*4+5500#

#T=5500(4/(9.81)+1)#

#T=5500(0.41+1)#

#T=5500*1.41#

#T=7755" "N#

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Answer 2

Tension in the support cable is 7700 N.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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