An electric toy car with a mass of #5 kg# is powered by a motor with a voltage of #8 V# and a current supply of #7 A#. How long will it take for the toy car to accelerate from rest to #7 m/s#?

Answer 1

The time is #=2.2s#

The voltage is #U=8V#
The current is #I=7A#

The power of the motor is

#P=UI=8*7=56W#
Velocity is #v=7ms^-1#
Mass is #m=5kg#

The kinetic energy of the car is

#KE=1/2mv^2=1/2*5*(7)^2=122.5J#

But,

#E=P*t#
The time is #t=(122.5)/56=2.2s#
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Answer 2

To find the time it takes for the toy car to accelerate from rest to 7 m/s, you can use the formula t=mvF t = \frac{m \cdot v}{F} , where t t is the time, m m is the mass of the car, v v is the final velocity, and F F is the force applied. First, calculate the force using the formula F=ma F = m \cdot a , where a a is the acceleration. Then, use Ohm's law to find the power P P of the motor, where P=VI P = V \cdot I . Finally, use the equation P=Fv P = F \cdot v to solve for a a . Once you have a a , plug it into the first equation along with the given values to find t t .

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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