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An automobile accelerates at 4 m/#s^2# from 20 m/s to 36 m/s. How long did that acceleration take?

Answer 1

Charles Aeschliman

#4 s#

According to the given information,

acceleration 'a' = 4 m/#s^2# initial velocity 'u' = 20 m/s final velocity 'v' = 36 m/s

Now, I have to find how long the acceleration of the automobile takes place. refer that 't' is time taken

Using equation, #v = u + at#

#rArr 36 = 20 + 4t#

value of 't' comes out to be 4 s.

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Answer 2

Lily Adams

To find the time it took for the acceleration, you can use the equation:

[ \text{Acceleration} = \frac{\text{Change in velocity}}{\text{Time}} ]

Rearranging the equation to solve for time:

[ \text{Time} = \frac{\text{Change in velocity}}{\text{Acceleration}} ]

Substituting the given values:

[ \text{Time} = \frac{36 , \text{m/s} - 20 , \text{m/s}}{4 , \text{m/s}^2} ]

[ \text{Time} = \frac{16 , \text{m/s}}{4 , \text{m/s}^2} ]

[ \text{Time} = 4 , \text{s} ]

So, the acceleration took 4 seconds.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.