An astronaut with a mass of #75 kg# is floating in space. If the astronaut throws an object with a mass of #6 kg# at a speed of #4/5 m/s#, how much will his speed change by?

Answer 1

The astronaut will get a velocity #0.064ms^-1# opposite to the direction of the object.

The problem stands on the conservation law of momentum. The formula is #m_1v_1+m_2v_2=m_1u_1+m_2u_2# Here primary momentum is 0 as the velocity of the man with the object was 0. So, #m_1v_1+m_2v_2=0# Let the mass of the astronaut is #m_1# and the object #m_2#and its velocity #v_2#. Then, #v_1#=#-(24/(75×5))#=-0.064 The -ve shows the direction to be opposite.
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Answer 2

The astronaut's speed will change by approximately 0.0533 m/s in the opposite direction of the thrown object.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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