Will the double displacement reactions below actually occur? Why or why not? Can a double displacement reaction occur if both products are aq???

Answer 1

All of these are solubility equilibria, in the first case driven by the formation of insoluble #AgCl#.....

#NaCl(aq) +AgNO_3(aq)rarrAgCl(s)darr + NaNO_3(aq)#

The precipitate of silver chloride is a white, curdy solid.

#Ba(NO_3)_2(aq) + 2KCl(aq) rightleftharpoons BaCl_2(aq) + 2KNO_3(aq)#
Here, the equilibrium mixture would simply contain #Ba^(2+)#, #K^+#, #NO_3^-#, and #Cl^-# ions......

The same goes for the previous response.

#Li_2SO_4(aq) + 2NH_4NO_3(aq) rarr 2LiNO_3(aq) + (NH_4)_2SO_4(aq)#

Here, there is no precipitation of an insoluble substance and the equilibrium mixture comprises lithium, ammonium, nitrate, and sulfate ions in solution.

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Answer 2

Yes, a double displacement reaction can occur even if both products are aqueous. It depends on whether the reactants form new compounds with each other, regardless of whether those compounds remain in solution or form precipitates, gases, or other products.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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