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ABCD is a rhombus . If angle ADB = 50 , find the angles of the rhombus ?

Answer 1

Caroline Aucoin

see explanation.

Some of the properties of a rhombus are :

1) The sides of a rhombus are all congruent (the same length.)
#=> AB=BC=CD=DA#

2) #AC and BD# are perpendicular.

3) #AO=OC, and BO=OD#

4) #DeltaAOB, DeltaCOB, DeltaCOD and DeltaAOD# are congruent

.................

Now back to our question,

Given that #angleADB=50^@=angleADO#,

#angle OAD=90-50=40^@#

#=> angleOBA=angleOBC=angleODC=ODA=50^@#
#=> angleOAB=angleOCB=angleOCD=angleOAD=40^@#

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Answer 2

Noah Atkinson

Since ABCD is a rhombus, opposite angles are congruent. Therefore, angle ABC = angle ADC. Since angle ADB = 50 degrees, and the sum of angles in a triangle is 180 degrees, angle ABC = angle ADC = (180 - 50) / 2 = 65 degrees. Therefore, the angles of the rhombus are all 65 degrees.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.