# AB is diameter whose center is O of a circle. If AC is 3 cm and BC is 4 cm, then find AB?

I have to assume point

In geometry, if

Given

by Pythagorean theorem,

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Since AB is the diameter of the circle, it is twice the radius of the circle. Therefore, AB = 2 * radius. The radius of the circle is half of the diameter, so if AC and BC are the legs of a right triangle, with AC being 3 cm and BC being 4 cm, then using the Pythagorean theorem, we can find the length of AB.

[AB^2 = AC^2 + BC^2]

[AB^2 = 3^2 + 4^2]

[AB^2 = 9 + 16]

[AB^2 = 25]

[AB = \sqrt{25}]

[AB = 5]

Therefore, the length of AB, the diameter of the circle, is 5 cm.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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