A wheel contains eight slices, numbered sequentially 1 through 8 The probability of landing on each slice is equal. The wheel is spun two times. What is the probability that the sum of the two spins is greater than 10?

Answer 1

There are #64# possible outcomes, from #1+1to8+8#

The favourable ones are the ones that add up to #>=11#
These are: #38,47,48,56,57,58,65,66,67,68,74,75,76,77,78,83,84,85,86,87,88# for a total of #21# (if you put this in a matrix with first spin as columns and second spin as rows it will be easier to see and count)
#->P(>10)=P(>=11)=21/64# or just under a third.
Or: For a first spin of #1or2# there is no possible favourable outcome. First spin #3->1# possible favourable outcome #(3+8#) First spin #4->2#, first spin #5->3#, etc. Then add #1+2+3+4+5+6=21#
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Answer 2

To find the probability that the sum of the two spins is greater than 10, we first need to determine all the possible outcomes when the wheel is spun twice. There are 8 slices, so there are (8 \times 8 = 64) total outcomes.

Next, we identify the outcomes where the sum of the two spins is greater than 10. These outcomes are: (4,7), (5,6), (6,5), (7,4), (7,5), (5,7), (8,3), (8,4), (3,8), and (4,8). There are 10 such outcomes.

Therefore, the probability of the sum of the two spins being greater than 10 is ( \frac{10}{64} = \frac{5}{32}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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