Home > Geometry > Perimeter and Area of Triangle

A triangle has two corners with angles of # pi / 12 # and # pi / 12 #. If one side of the triangle has a length of #4 #, what is the largest possible area of the triangle?

Answer 1

Sophia Alfred

Largest possible area of the triangle = 4

Given are the two angles #(pi)/12# and #pi/12# and the length 4

The remaining angle:

#= pi - (((pi)/12) + pi/12) =( 5pi)/6#

I am assuming that length AB (4) is opposite the smallest angle.

Using the ASA

Area#=(c^2*sin(A)*sin(B))/(2*sin(C)#

Area#=( 4^2*sin(pi/12)*sin((5pi)/6))/(2*sin(pi/12))#

Area#=4#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Jayden Jackson

The largest possible area of the triangle is ( 2\sqrt{3} ) square units.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.