A triangle has two corners of angles #pi /8# and #(2pi)/3 #. What are the complement and supplement of the third corner?

Answer 1

The supplement of the third corner angle#=19pi/24#.

The complement of the third corner#=7pi/24#.

The sum of corner angles of a triangle is #pi#.
We are given two corner angles #pi/8 and, 2pi/3#.
Therefore, the third corner angle #=pi-(pi/8+2pi/3)=pi-19pi/24#.
Hence, the supplement of the third corner angle#=pi-(pi-19pi/24)=19pi/24#.
The complement of the third corner#=pi/2-(pi-19pi/24)# #=19pi/24+pi/2--pi=(19pi+12pi-24pi)/24=7pi/24#.
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Answer 2

The complement of an angle is ( \frac{\pi}{2} ) minus the angle, and the supplement of an angle is ( \pi ) minus the angle.

For the given triangle:

  1. The complement of the third corner is ( \frac{\pi}{2} - \frac{\pi}{8} = \frac{3\pi}{8} ).
  2. The supplement of the third corner is ( \pi - \frac{2\pi}{3} = \frac{\pi}{3} ).
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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