A triangle has corners at points A, B, and C. Side AB has a length of #15 #. The distance between the intersection of point A's angle bisector with side BC and point B is #12 #. If side AC has a length of #36 #, what is the length of side BC?
Length of side BC = 40.8
Let the point where the angle bisector intersects with side BC be D
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40.8
I may have misinterpreted the question, but using the wonderful power of MS Paint:
Let D be the point at which the bisector of A meets BC. Let from the sine rule in from From the graph But
Let
Let
(I know I drew it wrong on the diagram, but)
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Using the Angle Bisector Theorem, we can determine the length of side BC.
The Angle Bisector Theorem states that in a triangle, an angle bisector divides the opposite side into segments that are proportional to the lengths of the other two sides.
Let D be the point where the angle bisector from A intersects side BC.
According to the theorem: BD/DC = AB/AC
Substitute the given values: 12/(BC - 12) = 15/36
Cross multiply and solve for BC: 12 * 36 = 15 * (BC - 12) 432 = 15BC - 180 15BC = 612 BC = 612/15 BC = 40.8
Therefore, the length of side BC is approximately 40.8.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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