A triangle has corners at #(6, 4 )#, ( 2, -2)#, and #( 5, -8)#. If the triangle is reflected across the x-axis, what will its new centroid be?
If you reflect across the x-axis, then the x-coordinates will not change and the y-coordinates will equal
Coordinates of centroid is [(x1 + x2 + x3)/3, (y1 + y2 + y3)/3]
hope that helped
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To find the centroid of the reflected triangle, you first find the centroid of the original triangle, then reflect it across the x-axis. The centroid of the original triangle is the average of its x-coordinates and the average of its y-coordinates.
Original centroid: x-coordinate = (6 + 2 + 5) / 3 = 13 / 3 ≈ 4.33 y-coordinate = (4 - 2 - 8) / 3 = -6 / 3 = -2
Reflected centroid: Reflect the y-coordinate across the x-axis: -(-2) = 2
So, the new centroid of the reflected triangle is (4.33, 2).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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