# A triangle has corners at #(3 ,4 )#, #(4 ,7 )#, and #(2 ,8 )#. How far is the triangle's centroid from the origin?

≈ 7 units

here

The 2 points here are the centroid and the origin Since the origin (0,0) is one of the points this simplifies the distance formula to

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Given the vertices of the triangle areTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can beTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculatedTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3,To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \fracTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{yTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7),To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), andTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 +To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + yTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2,To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 +To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + yTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8),To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8), theTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8), the centroidTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8), the centroid canTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8), the centroid can beTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8), the centroid can be calculatedTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\rightTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8), the centroid can be calculated byTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right)To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8), the centroid can be calculated by findingTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8), the centroid can be calculated by finding the average ofTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

ForTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8), the centroid can be calculated by finding the average of theTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the givenTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8), the centroid can be calculated by finding the average of the xTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangleTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8), the centroid can be calculated by finding the average of the x-coTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle withTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8), the centroid can be calculated by finding the average of the x-coordinatesTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8), the centroid can be calculated by finding the average of the x-coordinates and the average of the y-coordinates:

Average x-coordinate = (3To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8), the centroid can be calculated by finding the average of the x-coordinates and the average of the y-coordinates:

Average x-coordinate = (3 +To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3,To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Given the vertices of the triangle are (3, 4), (4, 7), and (2, 8), the centroid can be calculated by finding the average of the x-coordinates and the average of the y-coordinates:

Average x-coordinate = (3 + To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 +To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4),To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2)To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4,To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) /To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7),To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 =To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), andTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 AverageTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average yTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), weTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate =To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we canTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we can plugTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we can plug inTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 +To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we can plug in theseTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we can plug in these valuesTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we can plug in these values intoTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 +To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we can plug in these values into theTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we can plug in these values into the formula toTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8)To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we can plug in these values into the formula to findTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) /To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we can plug in these values into the formula to find theTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) / To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we can plug in these values into the formula to find the centroidTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) / 3To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we can plug in these values into the formula to find the centroid (To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) / 3 =To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we can plug in these values into the formula to find the centroid (GTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) / 3 = To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we can plug in these values into the formula to find the centroid (G).

To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) / 3 = 6To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we can plug in these values into the formula to find the centroid (G).

[To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) / 3 = 6.To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

For the given triangle with vertices (3, 4), (4, 7), and (2, 8), we can plug in these values into the formula to find the centroid (G).

[ G\To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) / 3 = 6.33 (To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\leftTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) / 3 = 6.33 (roundedTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\fracTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) / 3 = 6.33 (rounded toTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) / 3 = 6.33 (rounded to twoTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) / 3 = 6.33 (rounded to two decimalTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) / 3 = 6.33 (rounded to two decimal placesTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3},To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) / 3 = 6.33 (rounded to two decimal places)

To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) / 3 = 6.33 (rounded to two decimal places)

SoTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

Average x-coordinate = (3 + 4 + 2) / 3 = 3 Average y-coordinate = (4 + 7 + 8) / 3 = 6.33 (rounded to two decimal places)

So,To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, theTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 +To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of theTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangleTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle isTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 +To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is atTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3,To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\rightTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right)To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

NowTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now,To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ GTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, toTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to findTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\leftTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find theTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distanceTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\fracTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance betweenTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid andTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and theTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3},To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the originTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin,To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \fracTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, weTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we canTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can useTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use theTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distanceTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\rightTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formulaTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right)To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \textTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance}To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ GTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(xTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\leftTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 -To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - xTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3,To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \fracTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 +To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (yTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\rightTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right)To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 -To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - yTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

NowTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

Now,To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

Now, toTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

Now, to find theTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

Now, to find the distanceTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

Now, to find the distance betweenTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

Now, to find the distance between the centroid and the origin (0, 0), we can use the distance formula:

[ d = \sqrt{(x_2 - x_1)^2 + (y_To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

WhereTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

Now, to find the distance between the centroid and the origin (0, 0), we can use the distance formula:

[ d = \sqrt{(x_2 - x_1)^2 + (y_2To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where: To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

Now, to find the distance between the centroid and the origin (0, 0), we can use the distance formula:

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 -To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where: -To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - yTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates ofTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of theTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroidTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3,To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

PlTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in theTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33). To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinatesTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33). -To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates ofTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- (To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of theTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroidTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, yTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3,To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2)To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) \To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) )To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3)To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is theTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) andTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates ofTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the originTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the originTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0,To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0,To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0),To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we getTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \textTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ dTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{DistanceTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d =To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance}To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} =To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrtTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 -To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 -To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 +To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 +To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \leftTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\fracTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 -To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3}To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} -To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2}To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} \To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\rightTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \textTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2}To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{DistanceTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance}To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} =To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ dTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d =To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrtTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrtTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \leftTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\fracTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2}To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\rightTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2}To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} =To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrtTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ dTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d =To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 +To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrtTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.068To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 +To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689}To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} \To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 +To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{DistanceTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}}To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrtTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.068To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\fracTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689}To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}}To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approxTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 \To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10}To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

ThereforeTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore,To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, theTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

SoTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distanceTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So,To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distance betweenTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, theTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distance between the centroidTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, the distanceTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distance between the centroid ofTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, the distance betweenTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distance between the centroid of theTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, the distance between theTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distance between the centroid of the triangleTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, the distance between the centroid ofTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distance between the centroid of the triangle andTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, the distance between the centroid of theTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distance between the centroid of the triangle and theTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, the distance between the centroid of the triangle andTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distance between the centroid of the triangle and the originTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, the distance between the centroid of the triangle and theTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distance between the centroid of the triangle and the origin isTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, the distance between the centroid of the triangle and the originTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distance between the centroid of the triangle and the origin is approximatelyTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, the distance between the centroid of the triangle and the origin isTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distance between the centroid of the triangle and the origin is approximately To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, the distance between the centroid of the triangle and the origin is (To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distance between the centroid of the triangle and the origin is approximately 7To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, the distance between the centroid of the triangle and the origin is ( \To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distance between the centroid of the triangle and the origin is approximately 7 unitsTo find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, the distance between the centroid of the triangle and the origin is ( \sqrtTo find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distance between the centroid of the triangle and the origin is approximately 7 units.To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, the distance between the centroid of the triangle and the origin is ( \sqrt{To find the centroid of a triangle, you take the average of the x-coordinates and the average of the y-coordinates of its vertices. Then, you can use the distance formula to find the distance between the centroid and the origin.

So, the centroid of the triangle is at (3, 6.33).

Now, to find the distance between the centroid and the origin, we can use the distance formula:

[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Where:

- ( (x_1, y_1) ) is the coordinates of the centroid (3, 6.33).
- ( (x_2, y_2) ) is the coordinates of the origin (0, 0).

[ \text{Distance} = \sqrt{(0 - 3)^2 + (0 - 6.33)^2} ]

[ \text{Distance} = \sqrt{(-3)^2 + (-6.33)^2} ]

[ \text{Distance} = \sqrt{9 + 40.0689} ]

[ \text{Distance} = \sqrt{49.0689} ]

[ \text{Distance} \approx 7 ]

Therefore, the distance between the centroid of the triangle and the origin is approximately 7 units.To find the centroid of a triangle with vertices at (x1, y1), (x2, y2), and (x3, y3), the coordinates of the centroid (G) can be calculated using the formula:

[ G\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) ]

[ G\left(\frac{3 + 4 + 2}{3}, \frac{4 + 7 + 8}{3}\right) ]

[ G\left(\frac{9}{3}, \frac{19}{3}\right) ]

[ G\left(3, \frac{19}{3}\right) ]

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Plugging in the coordinates of the centroid (3, 19/3) and the origin (0, 0), we get:

[ d = \sqrt{(3 - 0)^2 + \left(\frac{19}{3} - 0\right)^2} ]

[ d = \sqrt{3^2 + \left(\frac{19}{3}\right)^2} ]

[ d = \sqrt{9 + \frac{361}{9}} ]

[ d = \sqrt{\frac{9 \cdot 9 + 361}{9}} ]

[ d = \sqrt{\frac{90}{9}} ]

[ d = \sqrt{10} ]

So, the distance between the centroid of the triangle and the origin is ( \sqrt{10} ) units.

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The centroid of a triangle can be found by averaging the coordinates of its vertices. In this case, the coordinates of the centroid are:

[ \left(\frac{{3 + 4 + 2}}{3}, \frac{{4 + 7 + 8}}{3}\right) ]

Solving this gives the centroid coordinates as (3, 6.33). To find the distance between this point and the origin, you can use the distance formula:

[ \text{{Distance}} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

where (x1, y1) is the origin (0, 0) and (x2, y2) is the centroid. Plugging in the values:

[ \text{{Distance}} = \sqrt{(3 - 0)^2 + (6.33 - 0)^2} ]

[ \text{{Distance}} = \sqrt{3^2 + 6.33^2} ]

[ \text{{Distance}} \approx \sqrt{9 + 40.1289} ]

[ \text{{Distance}} \approx \sqrt{49.1289} ]

[ \text{{Distance}} \approx 7.00 ]

So, the distance from the centroid to the origin is approximately 7.00 units.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- What are two lines in the same plane that intersect at right angles?
- Circle A has a center at #(11 ,2 )# and an area of #100 pi#. Circle B has a center at #(7 ,9 )# and an area of #36 pi#. Do the circles overlap? If not, what is the shortest distance between them?
- Are the planes #x+y+z=1# , #x-y+z=1# parallel, perpendicular, or neither? If neither, what is the angle between them?
- Circle A has a center at #(5 ,1 )# and an area of #23 pi#. Circle B has a center at #(2 ,8 )# and an area of #15 pi#. Do the circles overlap?
- A triangle has corners at #(9 ,3 )#, #(7 ,5 )#, and #(3 ,1 )#. How far is the triangle's centroid from the origin?

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