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A triangle has corners at #(3, 1 )#, #( 2, 3 )#, and #( 5 , 6 )#. If the triangle is dilated by # 2/5 x# around #(1, 2)#, what will the new coordinates of its corners be?

Answer 1

Sadie Adams

#color(blue)("New coordinates are " (9/5, 8/5), (7/5,12/5), (13/5,18/5)#

#A(3,1), B(2,3), C(5,6), " about point " D (1,2), " dilation factor "2/5#

#A'((x),(y)) =(2/5)a - (-3/5)d =(2/5)*((3),(1)) - (-3/5)*((1),(2)) = ((9/5),(8/5))#

#B'((x),(y)) = (2/5)b - (-3/5)d = (2/5)*((2),(3)) - (-3/5)*((1),(2)) = ((7/5),(12/5))#

#C'((x),(y)) = (2/5)c - (-35)d = (2/5)*((5),(6)) - (-3/5)*((1),(2)) = ((13/5),(18/5))#

#color(blue)("New coordinates are " (9/5, 8/5), (7/5,12/5), (13/5,18/5)#

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Answer 2

Caroline Aucoin

The new coordinates of the triangle's corners after dilation by ( \frac{2}{5} ) around (1, 2) will be:

Corner 1: (1.6, 1.8) Corner 2: (1.4, 2.4) Corner 3: (3.8, 3.2)

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