A trapezoid has a height of 6 cm and bases of 8 and 10 cm. What is the area of the trapezoid?

Answer 1

The area is 54 square centimeters, #cm^2#

Use the formula #A = ((a+b)*h)/2# Where #a# and #b# are the parallel sides, and #h# is the height of the trapezoid. A is the area of the trapezoid.
Let's define our variables: #a = 8 cm# #b = 10 cm# #h = 6 cm#

Let's put them into our formula:

#A = ((8cm + 10cm)*6cm)/2#
#A = (18cm * 6cm)/2#
#A = (108cm^2)/2#
#A = 54cm^2#
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Answer 2

The formula to find the area of a trapezoid is:

[ Area = \frac{1}{2} \times (base1 + base2) \times height ]

Given:

  • Height (( h )) = 6 cm
  • Base1 (( b_1 )) = 8 cm
  • Base2 (( b_2 )) = 10 cm

Substitute the given values into the formula:

[ Area = \frac{1}{2} \times (8 + 10) \times 6 ]

[ Area = \frac{1}{2} \times 18 \times 6 ]

[ Area = 9 \times 6 ]

[ Area = 54 ]

So, the area of the trapezoid is ( 54 , \text{cm}^2 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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