Home > Physics > Acceleration

A train accelerates at #-1.5# #m##/##s^2# for #10# seconds. If the train had an initial speed of #32# #m##/##s#, what is its new speed?

Answer 1

Elena Albarran

The new sped is #=17ms^-1#

Utilize the equation of motion.

#v=u+at#

The initial speed is #u=32ms^-1#

The acceleration is #a=-1.5ms^-2#

The time is #t=10s#

The ultimate velocity is

#v=u+at=32-1.5*10=32-15=17ms^-1#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Charles Aeschliman

#17m/s#

We can solve this by using the kinematic equation

#color(blue)(v=u+at#

Where,

#color(orange)(rarrv="final speed"#

#color(orange)(rarru="initial speed"#

#color(orange)(rarra="acceleration"#

#color(orange)(rarrt="time taken"#

As know #3# of the values, we can apply them

#rarrv=32+(-1.5)(10)#

#rarrv=32+(-15)#

#rarrv=32-15#

#color(green)(rArrv=17 m/s#

So, the train attained a speed of #17m/s#

Hope this helps....God bless ☻

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.