# A tank of nitrogen has a volume of 14.0 L and a pressure of 760.0 mm Hg. Find the volume of the nitrogen when its pressure is changed to 400.0 mm Hg while the temperature is held constant.

This question asks us to determine what would happen to the volume if the pressure were to change from one value to another. Pressure and volume are given.

We will use the Boyle' law equation; keep in mind that you must enter the values of volume and pressure into the equation in a precise manner. The pressure and volumes come in connected pairs, so you must enter them in the right places.

Using the formula for Boyle's law;

enter the values;

Divide and multiply:

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Using Boyle's Law, we can calculate the volume of the nitrogen gas at the new pressure:

(P_1V_1 = P_2V_2)

Given: (P_1 = 760.0 \text{ mm Hg}) (V_1 = 14.0 \text{ L}) (P_2 = 400.0 \text{ mm Hg})

Substituting the given values into the equation:

(760.0 \text{ mm Hg} \times 14.0 \text{ L} = 400.0 \text{ mm Hg} \times V_2)

(V_2 = \frac{760.0 \text{ mm Hg} \times 14.0 \text{ L}}{400.0 \text{ mm Hg}})

(V_2 = 26.6 \text{ L})

Therefore, the volume of the nitrogen gas when its pressure is changed to 400.0 mm Hg while the temperature is held constant is 26.6 L.

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