A student needs to make #5.00xx10^1# mL of a potassium carbonate solution with a concentration of #3.3000xx10^(-2)# mol/L. What mass of potassium carbonate should they use to make the solution? (Answer to 3 s.d. in g)
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To calculate the mass of potassium carbonate needed, you can use the formula:
mass = volume (in liters) * concentration (in mol/L) * molar mass (in g/mol)
Given: Volume = 5.00 × 10^1 mL = 5.00 × 10^1 mL / 1000 mL/L = 0.0500 L Concentration = 3.3000 × 10^(-2) mol/L Molar mass of potassium carbonate (K2CO3) = 2(39.10 g/mol) + 12.01 g/mol + 3(16.00 g/mol) = 138.21 g/mol
Now, plug the values into the formula:
mass = 0.0500 L * 3.3000 × 10^(-2) mol/L * 138.21 g/mol mass ≈ 2.292 g
Therefore, the mass of potassium carbonate needed to make the solution is approximately 2.292 grams (to 3 significant figures).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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