# A stop sign has the shape of a regular octagon. What is the sum of the interior angles of a stop sign?

Use the interior sum formula ..

hope that helped

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The sum of the interior angles can be calculated easily by understanding where the formula comes from.

For an octagon: Sum =

In any polygon, you can divide it up into triangles by joining one vertex to all of the others. You will find that the number of triangles is ALWAYS 2 less than the number of sides. ie 3 sides gives 1 triangle. 6 sides gives 4 triangles, 10 sides gives 8 triangles and so on.. But, the sum of the angles in any triangle is always 180°.

So, subtract 2 from the number of sides and multiply by 180°.

So the sum of the interior angles is:

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The sum of the interior angles of a regular octagon, including a stop sign, is ( (n - 2) \times 180^\circ ), where ( n ) is the number of sides of the octagon. Therefore, for a regular octagon, the sum of the interior angles is ( (8 - 2) \times 180^\circ = 6 \times 180^\circ = 1080^\circ ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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