# A stellar object is emitting radiation at 1670 nm. If the detector is capturing 9 * 10^7 photons per second at this wavelength, what is the total energy of the photons detected in one hour?

The equation used to calculate a photon's energy is;

In contrast, this represents a billionth of the energy released every second by a 100 watt lightbulb.

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To find the total energy of the photons detected in one hour, first calculate the energy of one photon using the formula E = hc/λ, where E is energy, h is Planck's constant (6.626 x 10^-34 J*s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. Then, multiply the energy of one photon by the number of photons detected per second, and finally multiply by the number of seconds in one hour (3600 seconds).

[ E = \frac{hc}{\lambda} ]

[ E = \frac{(6.626 \times 10^{-34} , \text{J*s})(3.00 \times 10^8 , \text{m/s})}{1670 \times 10^{-9} , \text{m}} ]

[ E = \frac{(1.988 \times 10^{-25} , \text{J*m})}{1670 \times 10^{-9} , \text{m}} ]

[ E = 1.19 \times 10^{-19} , \text{J} ]

[ \text{Total energy of photons detected in one second} = (1.19 \times 10^{-19} , \text{J}) \times (9 \times 10^7 , \text{photons/second}) ]

[ \text{Total energy of photons detected in one hour} = \text{Total energy of photons detected in one second} \times (3600 , \text{seconds/hour}) ]

[ \text{Total energy of photons detected in one hour} = (1.19 \times 10^{-19} , \text{J}) \times (9 \times 10^7 , \text{photons/second}) \times (3600 , \text{seconds/hour}) ]

[ \text{Total energy of photons detected in one hour} = 3.83 \times 10^{-11} , \text{J} ]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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