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A spring with a constant of #7 (kg)/s^2# is lying on the ground with one end attached to a wall. An object with a mass of #3 kg# and speed of #4 m/s# collides with and compresses the spring until it stops moving. How much will the spring compress?

Answer 1

Benjamin Asiedu

Pl, See the answer in the link below

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Answer 2

Adam Arnold

Use the formula: ( \text{Spring compression} = \frac{m \cdot v^2}{2k} ) Substitute values: ( \frac{3 , \text{kg} \cdot (4 , \text{m/s})^2}{2 \cdot 7 , \text{(kg)/s}^2} ) Calculate to get the spring compression.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.