A spring with a constant of #6 (kg)/s^2# is lying on the ground with one end attached to a wall. An object with a mass of #6 kg# and speed of #2 m/s# collides with and compresses the spring until it stops moving. How much will the spring compress?

Answer 1

the Kinetic energy #1/2 m v^2# after the collision and the compressione becomes the elastic energy of the spring #1/2 K X^2#. so # 1/2 m v^2 = 1/2 K X^2 # or # m v^2 = K X^2 # and resolving for X you have # X= sqrt(m/k) v= sqrt ((6Kg)/(6(Kg)/s^2)) 2m/s= 2m#

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Answer 2

Adam Arnold

[ x = \frac{mv}{k} ] [ x = \frac{(6 \ kg)(2 \ m/s)}{6 \ (kg)/s^2} ] [ x = 2 \ m ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.