A sphere has a negative charge of #6.4 xx 10^-7# coulombs. Approximately how many electrons must be removed to make the sphere neutral?

Answer 1

#4*10^12#electrons

Since one electron has a charge of #1.6*10^-19C# we can simply take the overall charge of the sphere and divide it by the charge of a single electron to see how many electrons account for the overall charge. It would look like

#(6.4*10^-4C)/(1.6*10^-19C)#

Which would give us #4*10^12#electrons

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Answer 2

William Audy

I got #4xx10^12# electrons

You know that one electron has a charge of #1.6xx10^-19C# so we need to remove: #(6.4xx10^(-7))/(1.6xx10^(-19))=4xx10^12# electrons

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Answer 3

Leo Abeyta

To find out how many electrons must be removed to make the sphere neutral, you divide the total charge by the charge of a single electron (which is approximately (1.6 \times 10^{-19}) coulombs). So, (\frac{6.4 \times 10^{-7}}{1.6 \times 10^{-19}}). Calculate to find the approximate number of electrons that must be removed.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.