A sonar pulse has a wavelength of 3.0 cm. If the pulse has speed in water of 1,500 m/s, what is its frequency?

Answer 1

#5.0xx10^4color(white)(i)Hz#

According to the universal wave equation, a wave's velocity is equal to the sum of its wavelength and frequency.

In terms of math,

#color(blue)(|bar(ul(color(white)(a/a)v=lambdafcolor(white)(a/a)|)))#
#ul("where")#: #v=#velocity of wave (metres per second) #lambda=#wavelength (metres) #f=#frequency (hertz or reciprocal seconds)

First, convert the provided wavelength between centimeters and meters.

#3.0color(white)(i)cmxxm/(100color(white)(i)cm)#
#=3.0color(red)cancelcolor(black)(cm)xxm/(100color(red)cancelcolor(black)(cm))#
#=0.030color(white)(i)m#
Step 2 Rearrange for frequency, #f#, in the universal wave equation.
#v=lambdaf#

Becomes,

#f=v/lambda#

Step 3: To find the pulse frequency, substitute the values you already know.

#f=(1500color(white)(i)m/s)/(0.030color(white)(i)m)#
#f=50000color(white)(i)Hz#

When the value is rounded to two significant figures,

#f=color(green)(|bar(ul(color(white)(a/a)color(black)(5.0xx10^4color(white)(i)Hz)color(white)(a/a)|)))#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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