A solution is made containing 22.8g of magnesium nitrate per 325g of water. What is the percent by mass of the solute?

Answer 1

Ellie Andrews

#"Approx. 7% (w/w)"#

#"Percentage by mass"# #=# #"Mass of solute"/"Mass of solution"xx100%# #=# #(22.8*g)/(325*g+22.8*g)xx100%=??%#

Why did I add the water and magnesium nitrate in bulk?

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Answer 2

Wyatt Atkins

To find the percent by mass of the solute, divide the mass of the solute (22.8g) by the total mass of the solution (22.8g + 325g), and then multiply by 100.

[ \frac{22.8}{22.8 + 325} \times 100 = \frac{22.8}{347.8} \times 100 ]

[ \frac{22.8}{347.8} \times 100 \approx 6.55% ]

The percent by mass of the solute is approximately 6.55%.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.