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A solution is made by dissolving 14.57g of sodium bromide in 415g of water. What is the molality of the solution?

Answer 1

Naomi Aronson

#"Molality"="Moles of solute"/"Kilograms of solvent"#

Regarding your issue,

#"Molality"=(14.57*g)/(102.89*g*mol^-1)xx1/(0.415*kg)# #~=# #0.342*mol*kg^-1#.

Would the #"molarity"# of the solution be different?

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Answer 2

Cooper Adams

To find the molality of the solution, first calculate the moles of sodium bromide using its molar mass (102.89 g/mol). Then, divide the moles of sodium bromide by the mass of the solvent (in kg).

Calculate moles of sodium bromide: Moles = mass / molar mass
Calculate molality: Molality = moles of solute / mass of solvent (in kg)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.