# A solid disk with a radius of #5 m# and mass of #4 kg# is rotating on a frictionless surface. If #3 W# of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at #4 Hz#?

The formula for "Torque" is "Power" / "Angular Velocity" = ("3 Watt") / ("2 π × 4 Hz") = "0.12 Nm"@

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To find the torque, use the equation:

[ \text{Torque} = \frac{\text{Power}}{\text{Angular velocity}} ]

Given:

- Power ((P)) = 3 W
- Angular velocity ((\omega)) = (2\pi \times \text{frequency}) (since the disk is rotating, (\omega = 2\pi \times \text{frequency}))

Substitute the values into the equation:

[ \text{Torque} = \frac{3}{2\pi \times 4} ]

[ \text{Torque} ≈ 0.119 , \text{Nm} ]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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