# A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is #9 # and the height of the cylinder is #6 #. If the volume of the solid is #135 pi#, what is the area of the base of the cylinder?

Cone volume plus cylinder volume equals solid volume.

Option 2)

The base area of the cylinder and the cone is equal because they have the same radius.

Cone volume plus cylinder volume equals solid volume.

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First, we find the volume of the solid:

Volume of cone = ( \frac{1}{3} \pi r^2 h ) Volume of cylinder = ( \pi r^2 h )

Given: Height of cone, ( h_{cone} = 9 ) Height of cylinder, ( h_{cylinder} = 6 ) Total volume = ( 135\pi )

From the given data, we can write: ( \frac{1}{3} \pi r^2 \times 9 + \pi r^2 \times 6 = 135\pi )

Solve this equation to find the radius (( r )). Then, once you have the radius, you can find the area of the base of the cylinder using the formula ( A = \pi r^2 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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