A soccer player kicks the ball to a height of 1 meter inside the goal. The equation for the height h of the ball at time t is #h=-4.9t^2-5t+2#, how do you find the time the ball reached the goal?

Answer 1

Please see the explanation for steps leading to the answer:
#t ~~ 1.19" s"#

Set h = 1 and the solve for t:

#1 = -4.9t^2 - 5t + 2#
#-4.9t^2 - 5t + 1 = #

Use the quadratic formula but discard the negative value, because negative time makes no sense:

#t = {5 + sqrt((-5)^2 -4(-4.9)(1))}/(2(4.9))#
#t = {5 + sqrt((-5)^2 -4(-4.9)(1))}/(2(4.9))#
#t ~~ 1.19" s"#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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