A sample of glass that has a mass of 6.0 g gives off 12 J of heat. If the temperature of the sample changes by 4.0°C during this change, what is the specific heat of the glass?

Answer 1

#0.50 J/(g^oC) #

To obtain the specific heat of that glass, let's use the equation below:

Based on the information you've provided, we know the following variables:

#DeltaT# = #4^oC#
#Q# = 12 J
#m# = #6.0g#

All we have to do is rearrange the equation to solve for #C#. This can be accomplished by dividing both sides by #m# and #Delta T# to get #C# by itself like this:

#C = Q/(DeltaTxxm)#

Now, we just plug in the known values:

#C = (12J)/(4^oC"xx6.0g)#

#C = 0.50J/(gxx^oC) #

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Answer 2

The specific heat capacity of the glass is 1.5 J/g°C.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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