A sample of gas at 35degree Celsius and 1 atm occupies a volume of 37.5L. At what temp should the gas be kept, if it required to reduce the volume to 3.0 litre at the same pressure?

Answer 1

The gas should be kept at -248 degrees C.

Apply Charles Law to determine the direct relationship between temperature and volume in degrees Kelvin (assuming constant pressure and molecular count).

# V_1/T_1 = V_2/T_2#
# V_1 = 37.5l# # T_1 = 35 + 273 = 308# degrees K # V_2 = 3.0l# # T_2 = unknown

These values can be substituted into the equation to get

# 37.5/308 = 3.0/ T_2# multiplying across gives
# T_2 = 308 xx 3.0/37.5# Which gives

T_2 = 24.6 degrees K

To find degrees C, subtract 273.

# 24.6 -273 = -248# degrees C. ( to three significant digits.)
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Answer 2

Using the combined gas law equation, rearranging to solve for the final temperature, and plugging in the given values:

(T_f = \frac{P_iV_iT_i}{P_fV_f})

(T_f = \frac{(1 , \text{atm})(37.5 , \text{L})(308 , \text{K})}{(1 , \text{atm})(3.0 , \text{L})})

(T_f \approx 1152 , \text{K})

So, the gas should be kept at approximately 1152 Kelvin to reduce the volume to 3.0 liters at the same pressure.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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