A red giant star has a temperature of 3,000 K and a luminosity #10^5# solar luminosities. How do you calculate the radius of the red giant in terms of the radius of the sun?

Answer 1

#=>R approx 33.33 " R"_ "sun"#

The relationship between luminosity, radius, and temperature can be reduced to the following when working with solar units:

#=>L = R^2T^4#
Solving for #R#:
#=>R = sqrtL/T^2 #
We are given #T = 3000 "K"# and #L = 10^5 "L"_ "sun"#. #R# in units of #"R"_ "sun"# is then:
#=>R = sqrt((10^5)^2)/3000 "R"_"sun"#
#=>R = 10^5/(3 xx 10^3) "R"_ "sun"#
#=>R = (1/3 xx 10^2)"R"_ "sun"#
#=>R = (100/3)"R"_ "sun"#
#=>color(green)( R approx 33.33 " R"_ "sun" )#
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Answer 2

The red giant star's radius can be found using the following formula: [ L = 4 \pi \sigma R^2 T^4 ] where: - ( L ) is the luminosity; - ( \sigma ) is the Stefan-Boltzmann constant ((5.67 \times 10^{-8} , \text{W m}^{-2} , \text{K}^{-4})); - ( R ) is the star's radius; - ( T ) is the temperature in Kelvin. Rearrange the formula to solve for ( R ): [ R = \sqrt{\frac{L}{4 \pi \sigma T^4}} ] Enter the given values to find the red giant star's radius in terms of the sun's radius.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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