A rectangle is 12cm longer than its wide. It's perimeter is 68m, how do you find it's length and width?
Length = 1706cm
Width = 1694cm
Perimeter = 68m = 6800cm
Length = x Width = 12 + x
Which means length is 1694 cm and width is 1694cm + 12cm = 1706cm
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Let the width of the rectangle be ( w ) cm. Then, the length of the rectangle is ( w + 12 ) cm.
The perimeter of a rectangle is given by the formula ( P = 2(w + l) ), where ( P ) is the perimeter, ( w ) is the width, and ( l ) is the length.
Given that the perimeter of the rectangle is 68 m, we can set up the equation:
[ 68 = 2(w + (w + 12)) ]
Solving this equation will give us the value of ( w ), which represents the width. Once we have the width, we can find the length by adding 12 to it.
[ 68 = 2(2w + 12) ] [ 34 = 2w + 12 ] [ 22 = 2w ] [ w = 11 ]
So, the width of the rectangle is 11 cm. Then, the length of the rectangle is ( w + 12 = 11 + 12 = 23 ) cm.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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