A reaction produced 5 moles of moles of O2. Predict how many moles of KClO3 will react given the following equation. 2KClO3 --> 2KCl + 3O2?

1) 3.3
2) 7.5
3) 5
4) 15

Answer 1

The answer is 1) 3.3

Balanced equation.

#"2KClO"_3("s")##rarr##"2KCl(s)" + "3O"_2("g")#
Multiply the given number of moles #"O"_2# by the mole ratio between #"KClO"_3# and #"O"_2# from the balanced equation, with #"KClO"_3"# in the numerator.
#5color(red)cancel(color(black)("mol O"_2))xx(2"mol KClO"_3)/(3color(red)cancel(color(black)("mol O"_2)))="3 mol KClO"_3# rounded to one significant figure

The answer is 1) 3.3, though, technically it should be rounded to one significant figure.

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Answer 2

If 5 moles of O2 are produced in the reaction, then according to the balanced chemical equation, 2 moles of KClO3 produce 3 moles of O2. Therefore, to find the moles of KClO3 that will react, we can set up a proportion:

(2 moles KClO3) / (3 moles O2) = (x moles KClO3) / (5 moles O2)

Solving for x:

2/3 = x/5 2*5 = 3x 10 = 3x x = 10/3 x = 3.33 moles of KClO3 will react.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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