# A ray of light travels from air into a liquid, The ray enters the liquid at an angle of 30.0°. The angle of refraction is 22.0°. Using Snell’s law, calculate the: index of refraction of the liquid. What might the liquid be?

Then refractive index

So the liquid is water

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The liquid is water

Snell's law states that:

where:

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Using Snell's Law:

n1 * sin(angle of incidence) = n2 * sin(angle of refraction)

Given:

- Angle of incidence (θ1) = 30.0°
- Angle of refraction (θ2) = 22.0°

Let n1 be the index of refraction of air, which is approximately 1.

Therefore,

1 * sin(30.0°) = n2 * sin(22.0°)

n2 = (sin(30.0°) / sin(22.0°))

n2 ≈ (0.5 / 0.374) n2 ≈ 1.34

The index of refraction of the liquid is approximately 1.34. Based on the common indices of refraction for liquids, this value suggests that the liquid might be water.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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