A pyramid with a square base has a volume of 320 and a height of 15. What is the perimeter of the base?

Answer 1

The perimeter of the base is #32#.

The following is the formula for a right rectangular pyramid's volume:

#V=(l*w*h)/3#, where #V=#Volume, #l=#length, #w=#width, and #h=#height.
Since the base is square, #l=w# so we can represent #l*w# as #l^2#
#V=(l^2*h)/3#

Using the previously provided values, we write:

#320=(l^2*15)/3#
#320=(l^2*5cancel15)/(1cancel3)#
Divide both sides by #5#.
#320/5=(l^2*5)/5#
#64=(l^2*1cancel5)/(1cancel5)#
#64=l^2#

Remembering that the answer must be a positive integer, find the square root of each side.

#8=l#
Since the length of the side of the base is #8#, and the base is a square, the perimeter will be:
#P=4l#
#P=4xx8#
#P=32#
The perimeter of the base is #32#.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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