A projectile is shot from the ground at a velocity of #8 m/s# and at an angle of #(2pi)/3#. How long will it take for the projectile to land?
To calculate the time of flight for the projectile, use the formula: ( \text{time} = \frac{2 \cdot \text{initial velocity} \cdot \sin(\text{launch angle})}{\text{acceleration due to gravity}} ). Substituting the given values: ( \text{time} = \frac{2 \cdot 8 \cdot \sin(\frac{2\pi}{3})}{9.8} ). Calculate to find the time.
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On the y axis,
When standing at your highest point,
Using the initial equation of motion,
Thus, it takes 0.692 seconds to reach the maximum height, and it takes 0.692 seconds for the projectile to descend to the ground from the highest point.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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