# A projectile is shot from the ground at a velocity of #4 m/s# at an angle of #pi/3#. How long will it take for the projectile to land?

Apply the motion equation:

We can calculate the time required to reach the maximum height because the final velocity is zero at this point.

This is where the equation changes to:

Radians to degrees conversion:

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To find the time it takes for the projectile to land, you can use the formula ( t = \frac{2v_0 \sin(\theta)}{g} ), where ( v_0 ) is the initial velocity, ( \theta ) is the launch angle, and ( g ) is the acceleration due to gravity. Substituting the given values, ( v_0 = 4 , \text{m/s} ), ( \theta = \frac{\pi}{3} ), and ( g = 9.8 , \text{m/s}^2 ), you get ( t = \frac{2 \times 4 \times \sin(\frac{\pi}{3})}{9.8} ). Solve for ( t ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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