# A projectile is shot from the ground at a velocity of #24 m/s# at an angle of #(5pi)/12#. How long will it take for the projectile to land?

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To find the time it takes for the projectile to land, you can use the equation:

[ t = \frac{2v_0 \sin(\theta)}{g} ]

where ( v_0 ) is the initial velocity (24 m/s), ( \theta ) is the angle of launch (( \frac{5\pi}{12} )), and ( g ) is the acceleration due to gravity (9.8 m/s²).

Substituting the values, you get:

[ t = \frac{2 \times 24 \times \sin\left(\frac{5\pi}{12}\right)}{9.8} ]

[ t \approx 3.15 , \text{seconds} ]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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