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A projectile is shot from the ground at a velocity of #19 m/s# at an angle of #pi/3#. How long will it take for the projectile to land?

Answer 1

Benjamin Asiedu

#t_e=3,35 " s"#

#v_i=19 " m/s initial velocity"#
#alpha=pi/3" angle"#
#g=9,81 m/s^2#
#t_e=? " elapsed time"#

#t_e=(2*v_İ*sin alpha)/g#

#t_e=(2*19*0,866)/(9,81)#

#t_e=3,35 " s"#

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Answer 2

Sebastian Acosta

To find the time of flight, use the formula: ( T = \frac{2 \cdot v_0 \cdot \sin(\theta)}{g} ), where ( v_0 = 19 , \text{m/s} ), ( \theta = \frac{\pi}{3} ), and ( g = 9.8 , \text{m/s}^2 ).

Substitute values into the formula to calculate ( T ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.