# A projectile is shot from the ground at a velocity of #18 m/s# and at an angle of #(2pi)/3#. How long will it take for the projectile to land?

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The time it takes for the projectile to land can be calculated using the formula: ( t = \frac{2v_0 \sin(\theta)}{g} ), where ( v_0 ) is the initial velocity (18 m/s), ( \theta ) is the launch angle ((2π)/3), and ( g ) is the acceleration due to gravity (approximately 9.8 m/s²). After substituting the given values into the formula, the time it takes for the projectile to land is approximately 3.66 seconds.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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