# A projectile is shot from the ground at a velocity of #12 m/s# and at an angle of #(pi)/2#. How long will it take for the projectile to land?

It will take 2.4 seconds for the projectile to land.

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To find the time it takes for the projectile to land, you can use the following formula for the vertical motion of a projectile:

[ t = \frac{2v_0\sin(\theta)}{g} ]

Where: ( v_0 = 12 ) m/s (initial velocity) ( \theta = \frac{\pi}{2} ) (angle of projection) ( g = 9.8 ) m/s² (acceleration due to gravity)

Plugging in the values:

[ t = \frac{2 \times 12 \times \sin\left(\frac{\pi}{2}\right)}{9.8} ]

[ t = \frac{2 \times 12 \times 1}{9.8} ]

[ t = \frac{24}{9.8} ]

[ t ≈ 2.45 ] seconds

So, it will take approximately 2.45 seconds for the projectile to land.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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