Home > Physics > Falling Objects

A projectile is shot from the ground at a velocity of #12 m/s# and at an angle of #(pi)/2#. How long will it take for the projectile to land?

Answer 1

Elena Albarran

Here, #u= 12m/s# , #theta = pi/2#

#t = (2usintheta)/g#

#t= (2xx12xx1)/10#

#t= 2.4 sec#

It will take 2.4 seconds for the projectile to land.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

William Audy

To find the time it takes for the projectile to land, you can use the following formula for the vertical motion of a projectile:

[ t = \frac{2v_0\sin(\theta)}{g} ]

Where: ( v_0 = 12 ) m/s (initial velocity) ( \theta = \frac{\pi}{2} ) (angle of projection) ( g = 9.8 ) m/s² (acceleration due to gravity)

Plugging in the values:

[ t = \frac{2 \times 12 \times \sin\left(\frac{\pi}{2}\right)}{9.8} ]

[ t = \frac{2 \times 12 \times 1}{9.8} ]

[ t = \frac{24}{9.8} ]

[ t ≈ 2.45 ] seconds

So, it will take approximately 2.45 seconds for the projectile to land.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.